input = "1"

def look_and_say(input):
	s = ""
	last = 'x'
	count = 1

	for n in input:
		if last == 'x':
			last = n
			count = 1
			continue;

		if last == n:
			count += 1
			continue;

		s+=f"{count}{last}"
		
		last=n
		count=1

	return s+f"{count}{n}"


""" Not worth it
def recursive_look_and_say(input):
	j = len(input)//2

	while True:
		if j == len(input)-1:
			return look_and_say(input)

		# Assert 'j' does not divide repeating characters
		if input[j] != input[j+1]:
			return recursive_look_and_say(input[:j+1])+ recursive_look_and_say(input[j+1:])

		j+=1
"""


# Result

for i in range(50):
	input = look_and_say(input)
print(len(input))